මේ වැඩේ හිතුවට වඩා සංකීර්ණයි. කොහොම හරි O(n2) solution එකක් හොයා ගත්තා.
interface Steps extends Record<string, any> {
startDate: String;
endDate: String;
steps: Number
}
interface Distance extends Record<string, any> {
startDate: String;
endDate: String;
distance: Number
}
let steps: Array<Steps> = [
{ startDate: '2020-10-21', endDate: '2020-10-22', steps: 101 },
{ startDate: '2020-10-22', endDate: '2020-10-23', steps: 102 },
{ startDate: '2020-10-24', endDate: '2020-10-25', steps: 103 }
];
let activity: Array<Distance> = [
{ startDate: '2020-10-21', endDate: '2020-10-22', distance: 101 },
{ startDate: '2020-10-22', endDate: '2020-10-23', distance: 102 },
{ startDate: '2020-10-26', endDate: '2020-10-26', distance: 103 }
];
function join<L extends Record<string,any>, R extends Record<string,any>>(left: Array<L>, right: Array<R>, by: Array<string>) {
const joined: Array<L&R> = [];
for (let l of left) {
const fromRight = right.find(r => by.every((curr) => (r[curr] == l[curr]), true))
if (fromRight === undefined)
continue;
joined.push({ ...fromRight, ...l})
}
return joined;
}
console.log(join(steps, activity, ['startDate', 'endDate']))
/*
[LOG]: [{
"startDate": "2020-10-21",
"endDate": "2020-10-22",
"distance": 101,
"steps": 101
}, {
"startDate": "2020-10-22",
"endDate": "2020-10-23",
"distance": 102,
"steps": 102
}]
*/
Types දාපු හැටි හරිද දන්නෑ. logic එක නං හරි.
