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මේ වැඩේ හිතුවට වඩා සංකීර්ණයි. කොහොම හරි O(n2) solution එකක් හොයා ගත්තා.

interface Steps extends Record<string, any> { 
    startDate: String; 
    endDate: String; 
    steps: Number
}

interface Distance extends Record<string, any> { 
    startDate: String; 
    endDate: String; 
    distance: Number
}

let steps: Array<Steps> = [
    { startDate: '2020-10-21', endDate: '2020-10-22', steps: 101 }, 
    { startDate: '2020-10-22', endDate: '2020-10-23', steps: 102 },
    { startDate: '2020-10-24', endDate: '2020-10-25', steps: 103 }
];

let activity: Array<Distance> = [
    { startDate: '2020-10-21', endDate: '2020-10-22', distance: 101 }, 
    { startDate: '2020-10-22', endDate: '2020-10-23', distance: 102 },
    { startDate: '2020-10-26', endDate: '2020-10-26', distance: 103 }
];

function join<L extends Record<string,any>, R extends Record<string,any>>(left: Array<L>,  right: Array<R>,  by: Array<string>) {
    const joined: Array<L&R> = [];

    for (let l of left) {
        const fromRight = right.find(r => by.every((curr) => (r[curr] == l[curr]), true))
        if (fromRight === undefined)
            continue;
        joined.push({ ...fromRight, ...l})
    }

    return joined;
}

console.log(join(steps, activity, ['startDate', 'endDate']))
/*
[LOG]: [{
  "startDate": "2020-10-21",
  "endDate": "2020-10-22",
  "distance": 101,
  "steps": 101
}, {
  "startDate": "2020-10-22",
  "endDate": "2020-10-23",
  "distance": 102,
  "steps": 102
}] 
*/

Types දාපු හැටි හරිද දන්නෑ. logic එක නං හරි.

Playground link