$grouped = $collection->groupBy('foreignkey_id');

@root welcome bro

thank you, I'll find out :smile:

thanks @Danuva & @thilanka

@fern Ohh this very simple. Thnx Bro

Thank you

@ciaompe ow bro niyamai site eka superb.

@kushanshanuka
Ou machan puluwan, meka godak advanced widiyata use karanna puluwan

Hello Udith Thanks , will publish other tutorials asap

node js <3

<?php $permissions = ['create_user', 'create_post','edit_post', 'delete_post', 'edit_user', 'delete_user']; $permission_categories = []; foreach ($permissions as $value) { $name = explode("_", $value); # hasn't key if(!array_key_exists($name[1], $permission_categories)){ $permission_categories[$name[1]] = []; } $permission_categories[$name[1]][] = $name[0]; } print_r($permission_categories);

I <3 Laravel, thanks for the sharing.

@akashmanujaya i have done small change to code, try this

function saveData() { var confirmed = document.getElementById('confirmed').checked ? 1 : 0; var id = document.getElementById('id').value; var Condition=$('input[name="Condition"]:checked').val(); //check this line var fd = new FormData(); fd.append('confirmed', confirmed); fd.append('id', id); fd.append('Condition',Condition); //uncomment this line }

@akashmanujaya welcome bro...

@Tize-Thamizh you can easily find better English tutorials online. (like https://www.w3schools.com/nodejs/nodejs_intro.asp). I simply wrote this for beginners who likes to learn stuff in native language.

Did you find the answer?

@ciaompe my pleasure bro...

The Answer is Via API. If you are new to API development. Please refer the API fundamentals before start.